Question

() If [2x-(-y)=16] and [3x-2y]=3,
form two simultaneous equation from the given determinants and solve

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Answer 1

Answer:

21−yx∣∣∣=16  ∣∣∣3y2x∣∣∣=3

∴2×(x)−(−y)×1=16∴3×x−2×y=3

∴2x+y=16…..(1)∴3x−2y=3……(2)

Multiplying equation (1) by 2,

4x+2y=32…….(3)

Adding equations (2) and (3),

3x−2y=3 ...(2)4x+2y=32 ...(3)7x =25¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∴x=357∴x=5

Substituting x=5 in equation (1) ,

2(5)+y=16∴10+y=16∴y=16−10∴y=6

Step-by-step explanation: