If 2x+y=32and 3x+y=68 find the value of x/y
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1
therefore multiply first eqn by 3 we get 6x+3y=96 similarly we get on multiplying the second eqn by 2,6x+2y=136 so on subtracting second equation from first equation we get y=-40 and x=36 therefore x/y =-0.9
Answered by
2
2x+y=32
3x+y=68
- - -
-x=-36
X=36
Put tge value of x=36 in equation. 1
2(36)+y=32
Y=-40
3x+y=68
- - -
-x=-36
X=36
Put tge value of x=36 in equation. 1
2(36)+y=32
Y=-40
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