If 2x+y = 35 and 3x+3y = 65.
Solve the system of equation.
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Given =》
1) 2x+y=35————(1)
2) 3x+3y=65———(2)
Solution =》
2x+y=35————(1)
3x+3y=65———(2)
Multiply eq1 by 3 and eq2 by2
3(2x+y=35)
= 6x+3y=70————(3)
2(3x +3y=65)
= 6x+6y = 130————(4)
Subtract eq4 from eq3
6x + 6y = 130
6x + 3y = 70
- - -
——————–
3y = 60
y=60/3
y= 20
putting value of y in eq 1
2x+y=35
2x+20=35
2x=35-20
x=15/2
x=7.5
so, the value of x and y is 20 and 7.5
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