If [(2x+y, 3y)(0,4)] = [(6,0)(0,4)] then find the value of x.
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Answered by
3
According to the question,
2x+y= 6.....eq.1
and,
3y= 0
=> y= 3/0
=> y= 0
Substituting y=0 in eq.1,
2x+0=6
=> 2x=6
=> x= 6/2
=> x= 3
2x+y= 6.....eq.1
and,
3y= 0
=> y= 3/0
=> y= 0
Substituting y=0 in eq.1,
2x+0=6
=> 2x=6
=> x= 6/2
=> x= 3
Answered by
0
(2x+y, 3y) = (6,0)
3y = 0
=> y = 0
2x+y = 6
=> 2x = 6
=> x = 6/2
=> x = 3
:. x = 3
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