If 2x + y=6 amd xy=4 then find the value of (2x-y)
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(2x+y)^2 = (2x)^2 + (y)^2 + 2(2x)(y)
(6)^2 = 4x^2 + y^2 + 4xy
36 = 4x^2 + y^2 + 4(4)
36-16 = 4x^2 + y^2
20 = 4x^2 + y^2 ....(i)
(2x-y)^2 = 2x)^2 + (y)^2 - 2(2x)(y)
(2x-y)^2 = 4x^2 + y^2 - 4xy
(2x-y)^2 = 20 - 16
(2x-y)^2 = 4
2x-y = 2
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