Math, asked by sudhanesankaiga, 1 year ago

If 2x + y=6 amd xy=4 then find the value of (2x-y)

Answers

Answered by akkritisharma23
2

Answer:

Step-by-step explanation:

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Answered by kiritobeater645
3

Answer:

(2x+y)^2 = (2x)^2 + (y)^2 + 2(2x)(y)

(6)^2 = 4x^2 + y^2 + 4xy

36 = 4x^2 + y^2 + 4(4)

36-16 = 4x^2 + y^2

20 = 4x^2 + y^2 ....(i)

(2x-y)^2 = 2x)^2 + (y)^2 - 2(2x)(y)

(2x-y)^2  = 4x^2 + y^2 - 4xy

(2x-y)^2  = 20 - 16

(2x-y)^2 = 4

2x-y = 2

Step-by-step explanation:

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