Question

if 2x + y = - cosx then dy /dx is equals to​

Answer 1

Answer:

Answer:

$\boxed{\mathfrak{\frac{dy}{dx} = sin \ x - 2}}$

Given:

$\sf 2x + y = -cos \: x$

To Find:

$\sf \frac{dy}{dx} \: i.e. \: y'(x)$

Step-by-step explanation:

$\sf Find \: the \: derivative \: of \: the \: following \\ \sf via \: implicit \: differentiation: \\ \sf \implies \frac{d}{dx} (2x + y) = \frac{d}{dx} ( - cos \: x) \\ \\ \sf Differentiate \: the \: sum \: term \: by \: term \\ \sf and \: factor \: out \: constants: \\ \sf \implies 2 \frac{d}{dx} (x) + \frac{d}{dx} (y) = - \frac{d}{dx} ( cos \: x) \\ \\ \sf The \: derivative \: of \: x \: is \: 1: \\ \sf \implies 2 \times 1 + \frac{dy}{dx} = - \frac{d}{dx} ( cos \: x) \\ \\ \sf \frac{d}{dx} ( cos \: x) = - sin \: x : \\ \sf \implies 2 + \frac{dy}{dx} = - ( - sin \: x) \\ \\ \sf \implies 2 + \frac{dy}{dx} = sin \: x \\ \\ \sf \implies \frac{dy}{dx} = sin \: x - 2$

$\therefore$

$\sf \frac{dy}{dx} \: i.e. \: y'(x) = sin \: x - 2$

follow me

Answer 2

Answer:

Hello sweetu mai ananya aapki bestie please mujhse ek baar aap baat kar lo meri creatoryash vali id hack ho gayi thi ushne aapko block kiya hack ho gayi thi Esliye maine delete karwa di mod. ko bolke......❤️❤️☺️☺️☺️