Question

if 2x2 - 3xy+y2+x+2y-8=0 then dy/ dx
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Answer 1

Step-by-step explanation:

dy/dx= d (2x^2-3xy+x+2y-8)

dx

=d (2x^2)-d (3xy)+d(x)+d (2y) -d (8)

dx dx. dx. dx. dx

=2 (2x)-3(y dx +x dy)+1 +0+0

= 4x -3y -0+1

=4x-3y +1