Question

If 2x²+3y²+4z²-√6xy-2√3yz-2√2xz=0, then find the value of (2x²+3y²+16z²+2√6xy-8√3yz-8√2xz)

Answer 1

(i) 4x 2 - 3x + 7 => In one variable. Only unknown in this expression is x.
(ii) y² + √2 => In one variable.Only (i) 4x 2 - 3x + 7 => In one variable. Only unknown in this expression is x.,
(ii) y² + √2 => In one variable.Only unknown is y
(iii) 3√t + √2 => In one variable.Only unknown is t
(iv) y + 2/y => In one variable.Only unknown is t
(v) x 10 +y 3 + t 50 => Not in one variable.There are three variables x, y and t.
2. Write the coefficients of x² in each of the following:
(i) 2 + x² + x => coefficient of x² is 1.
(ii) 2 – x² + x³ => coefficient of x² is -1.
(iii) (π/2)x² + x => coefficient of x² is π/2.
(iv)√2x - 1 => coefficient of x² is 0. is y
(iii) 3√t + √2 => In one variable.Only unknown is t
(iv) y + 2/y => In one variable.Only unknown is t
(v) x 10 +y 3 + t 50 => Not in one variable.There are three variables x, y and t.
2. Write the coefficients of x² in each of the following:
(i) 2 + x² + x => coefficient of x² is 1.
(ii) 2 – x² + x³ => coefficient of x² is -1.
(iii) (π/2)x² + x => coefficient of x² is π/2.
(iv)√2x - 1 => coefficient of x² is 0.