If 2x² - 4x + c = 0 has equal roots, then find the value of C
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Answer: hi friend !
4x2 - 2(c+1)x +(c+4) =0
using quadratic formula
a = 4x2 = 8
b = -2(c+1)
c = (c+4)
D = b2 - 4ac
= 4(c+1)2 - 4(c+4) (8)
= 4 (c2 +2c +1) - 32(c+4)
= 4c2 +8c +4 -32c-128
= 4c2 - 24c - 124
4c2 - 24c -124 =0 (since the roots are real and equal b2-4ac = 0)
divide by 4
c2 -6c - 31 =0
a=1 b= -6 c= -31
D = b2- 4ac
= 36 - 4 (-31)
= 36 + 124
=160 (root of 160 = 40)
c = 6 + 40 / 2
= 46/2
=23
c = 6 - 40/2
= -34 /2
= --17
c can be -17 or 23
or
the answer is -17 or 23
Step-by-step explanation:
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