Question

If 2x² + x +a is divided by (x – 3), leaves the remainder is 1 then find value of a
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Answer 1

Let p(x) = $2x^{2} +x+a$

Put, $x=3$ in p(x)

$2(3^{2} ) + 3 +a =1$

$a+21=1$

$a=1-21$

$a=-20$

MARK AS BRAINLIEST, IF YOU FIND IT RIGHT.

Answer 2

Answer:-20

Step-by-step explanation:

we divide the equation and get the quotient as 2x+7

and remainder as 21+a

now 21+a=1

so solving this we got a as -20