Question

If 2x2 + xy - 3y2 + x + ay - 10 = (2x + 3y + b)
(x - y - 2) the value of a and b are
(1) 11 and 5
(2) 1 and 5
(3) -1 and 5
4) -11 and 5​

Answer 1

Answer:

Given equation:

2x

2

+xy−3y

2

+x+ay−10=(2x+3y+b)(x−y−2)

⇒2x

2

+xy−3y

2

+x+ay−10=2x

2

+3xy+bx−2xy−3y

2

−by−4x−6y−2b

⇒2x

2

+xy−3y

2

+x+ay−10=2x

2

+xy−3y

2

+(b−4)x−(b+6)y−2b

Comparing the coefficients of x,y and constants will get:

b−4=1..(i)

−(b+6)=a..(ii)

−2b=−10..(iii)

From eq(1), we get

⇒b=5

Now put b in eq(2), we get

⇒−(b+6)=a

⇒a=−11

From eq(3), we get

⇒−2b=−10

⇒b=5

Hence values of a,b are −11,5

Answer 2

Answer:11 and 5

Step-by-step explanation: