Question

if 2x³+ax²+bx-6 has(x-1) as a factor and leaves a
reminder to when divided by (x-2) find the values of (a) and(b) ​

Answer 1

Answer:

Answer

f(x)=2x3+ax2+bx−6

(x−1) is a factor

∴f(1)=0⇒2+a+b=6

⇒a+b=4→1

and f(x) leaves remainder 2 on being divided by (x−2)

∴f(2)=2

⇒2×23+a×22+b×2−6=2

⇒4a+2b+16−6=2

⇒4a+2b=2−10=−8

⇒2a+b=−4

Solving 1 and 2

2a+b=−4

a+b=4

−−−

a=−8

a+b=4

−8+b=4

b=4+8=12

∴a=−8;b=12

Answer 2

Answer:

u can see in the pic

Step-by-step explanation:

hope it'll help you