Question

If 2y + 1by2y = L and 2y - 1by2y = m , then l² - m² = _______. I want an solution for this question.

Answer 1

Answer:

8y

Step-by-step explanation:

is the answer

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Answer 2

Answer:

I think the ans is $l^{2} - m^{2} = \frac{1}{2y}$

Step-by-step explanation:

because we have given,

                              $\frac{2y+1}{2y} =l$    and      $\frac{2y-1}{2y} =m$

so,                         =  $[\frac{2y+1}{2y} ]^{2} -[\frac{2y-1}{2y} ]^{2}$         (∵ $l^{2} -m^{2}$ )

and                        = $4y^{2} +4y+1/4y^{2} - 4y^{2} +4y-1/4y^{2}$    [∵ $(a+b)^{2} , (a-b)^{2}$ ]

and                        = $4y^{2} -4y^{2} +4y+4y+1-1/ 4y^{2}$

and                        = $8y/4y^{2}$

and                        = $\frac{1}{2y}$

so, the ans is  $\frac{1}{2y}$ .

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