Question

if (2y+3x):(3y+5x)=18:29,find x^3:y^3

Answer 1

Answer :

64/27

step by step explaination :

(2y+3x)29 = 18(3y+5x)

58y+87x = 54y+90x

(58-54)y=(90-87)x

4y=3x

4/3=x/y

now putting the value of x/y in x³/y³

x³/y³= 4³/3³= 64/27

JAI SHREE KRISHNA

Answer 2

(2y+3x)29 =(3y+5x)18
58y+87x = 54y+90x
58y-54y =90x -87x
4y = 3x
4/3= x/y

Now
x^3/y^3= 4^3/3^3
= 64/27 ........ ans