If 3.01 Ã 10^20 molecules are removed from 98 gm of
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If 3.01 ,*10^20 molecules are removed from 98 mg of ... 9.8/98 = 98/98* 10 = 0.1 Therefore 0.1 moles are in 9.8 gm.
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0.1 moles r 9.8 gm
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