Question

If 3.01 X 1020 molecules are removed from 98 mg of H2SO:, then find the number of moles of H2S0, left.​

Answer 1

Answer:

In case 3.01 ,*10^20 atoms are expelled from 98 mg of H2So4 then the quantity of moles of H2SO4 left are Molecular mass of H2SO4=2+32+64=98g consequently 98 g of sulphuric corrosive will contain 6.02*10^23 particles 6.02*10^23=1mole 3.01*10^23=1/2mole 0.5 moles of H2SO4 are left