Question

if 3.01 x10^20 molecules are removed from 98 mg of h2so4 then find out the mass of oxygen in the h2so4 left behind​

Answer 1

Answer:

32mg

Explanation:

No of molecules in 98 mg of H2SO4=(98/1000)*98mole

=N/1000=6.010^20

so left molecule= 6.02x10^20-3.01x10^20

=3.01x19^20

Now mass of oxygen in one mole h2so4 = 64gm

so mass of o2 in left h2so4=

(3.01x10^20/6.02x10^23)*64gm

=32/1000 gm

=32mg