if√3+1/√3-1=a+b√2,find the values of a and b
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√3+1/√3-1
rationalize
(√3+1)(√3+1)/(√3-1)(√3+1)
using (a-b)(a+b)=a²-b²
(a+b)²= a²+b²+2ab
(√3+1)²/(√3)²-(1)²
3+1+6/3-1
10/2
5
√3+1/√3-1=a+b√2
5=a+b√2
therefore, a=5 and b=0
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