Question

if (3,-1) and (6, 1) lies on the line of equation px+qy=9 then find the value of p and q​

Answer 1

Answer:

Step-by-step explanation:

(3,-1) x value=3, y value=(-1)

(6,1) x value=6, y value=1

These points are on the equation.

So we can make two equations

By (3,-1)

p*3+q*(-1)=9

This multiply by 2

Then p*3*2+q*(-1)*2=9*2

p*6-2*q=18 ;A

By(6,1)

p*6+q*1=9 ;B

Now, equation A- equation B

p*6-2*q-p*6-q*1=18-9

-3*q=9

q=(-3)

Then by equation A

p*6-2*q=18

p*6-2*(-3)=18

p*6+6=18

p*6=12

p=12/6

p=2