If (3,1) is the point of intersection of the lines ax+by=7 & bx+ay=5 then find the values of a and b
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put x=3 and y=1
a×3+b×1=7
b×3+a×1=5
a×1+b×3=5
3a+b=7-------------------(1)equation
a+3b=5 -------------------(2) equation
multiply (2) by 3
3a+b=7---------------(1)
3a+9b=15---------------(3)
subtracting (3) From (1)
3a+b=7 ------------(1)
(-) 3a+9b=15-----------(3)
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- - -
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-8b=-8
b=-8/-8
b=1
put b=1 In (1)
3a+b = 7
3a+1=7
3a=7-1
3a=6
a=6/3
a=2
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