Question

If 3 *10^-3J of work is done in moving a particle carrying a charge of 15*10^-6C from infinity to a point P, what will be the potential at the pont P?

Answer 1

v=w/q
v=3*10-3/15*10-6c
v=200v
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Answer 2

Explanation:

we know that V = W/Q

thus:- V= 3×10^-3 ÷ 15×10^-6

V= 200 volt......

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