Math, asked by nidhi2312, 8 months ago

If 3^1215 = n^n, where 'n' is a natural number, what is the value of 'n'?​

Answers

Answered by menkagiri86
5

Answer:

I am weak in maths I am so

Answered by ansiyamundol2
0

Answer:

The value of n is 243.

Step-by-step explanation:

It is given that : 3^{1215} =n^{n}

1215=243*5

(3^5)^{243}  = n^n

243^{243}  = n^n

By comparing the indices of LHS and RHS,

n=243

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