If 3 =18 and =6,find the value of 27x^3+64y^6
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Answer:
sᴇᴀʀᴄʜ-ɪᴄᴏɴ-ʜᴇᴀᴅᴇʀ
sᴏʟᴜᴛɪᴏɴ
ᴠᴇʀɪғɪᴇᴅ
ᴠᴇʀɪғɪᴇᴅ ʙʏ ᴛᴏᴘᴘʀ
ɪᴛ ɪs ɢɪᴠᴇɴ ᴛʜᴀᴛ 3x+2ʏ=12 ᴀɴᴅ xʏ=6.
ᴡᴇ ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ 27x
3
+8ʏ
3
ᴀs sʜᴏᴡɴ ʙᴇʟᴏᴡ:
27x
3
+8ʏ
3
=(3x)
3
+(2ʏ)
3
=(3x+2ʏ)[(3x)
2
−(3x×2ʏ)+(2ʏ)
2
](∵ᴀ³+ʙ³=(ᴀ+ʙ)(ᴀ²−ᴀʙ+ʙ²))
=12[(3x)
2
−(6×xʏ)+(2ʏ)
2
](∵3x+2ʏ=12,xʏ=6)
=12[(3x)
2
−(6×6)+(2ʏ)
2
]
=12[(3x)
2
−36+(2ʏ)
2
]
=12[(3x)
2
+(2ʏ)
2
+(2×3x×2ʏ)−(2×3x×2ʏ)−36]
=12[(3x+2ʏ)
2
−12xʏ−36]
=12[(12)
2
−(12×6)−36]
=12(144−72−36)
=12(144−108)
=12×36
=432
ʜᴇɴᴄᴇ, 27x
3
+8ʏ
3
=432.
Step-by-step explanation:
Hp it hlps ☺️ ✌️ ☺️
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