Question

.if √3+√2/√3-√2 = a+b √6 find the value of a and b

Answer 1

√3+√2/√3-√2 = a+b √6

All you need to do is first rationalize the denominator
(√3+√2)(√3+√2)/(√3-√2) (√3+√2) =a+b √6

= (3 +2 +2√6)/ 1 = a+b√6
= 5 +2√6 = a+b√6



So, a=5 and b = 2

Answer 2

√3+√2/√3-√2 ×√3+2/√3+√2
3+√6+√6+4/3-2
7 +2√6