Question

if √3+√2/√3-√2=a+b√6, find the values of a and b​

Answer 1

Answer:

a=5, b=2

Step-by-step explanation:

$\frac{\sqrt{3}+\sqrt{2} }{\sqrt{3}-\sqrt{2} }$

=$\frac{\sqrt{3}+\sqrt{2} }{\sqrt{3}-\sqrt{2} }$×$\frac{\sqrt{3}+\sqrt{2} }{\sqrt{3}+\sqrt{2} }$             [Rationalizing the denominator]

=$\frac{3+2+2\sqrt{6} }{3-2}$

=$\frac{5+2\sqrt{6} }{1}$

=a+b√6

⇒a=5, b=2

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