If (√3+√2) ÷ (√3-√2)= a + b√6, then a =
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(root 3+root 2)/(root 3-root2)=a+broot6
root 3 +root 2)/(root 3-root2)=1 cutsort
1=a+b root 6
therefore
a=1-b root 6
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