Math, asked by shibanechamuah, 6 months ago

If 3/2 is a root of the quadratic equation x2-mx-5/4=0, then value of m is:???


Answers

Answered by Binnisingh94764
2

Answer:

(3/2)2-m(3/2)-5/4=0

9/4-3/2m-5/4=0

9-6m-5

_______=0

4

4-6m=0

-6m=-4

m=-4/-6

m=2/3

Answered by TS18
0

Answer:

m=2/3

Step-by-step explanation:

Given, p(x)= x2-mx-5/4

p(3/2)= (3/2)2-m(3/2)-5/4

=9/4-3m/2-5/4

= (9-6m-5)/4

=(4-6m)/4

=(2-3m)/2

Now,

(2-3m)/2=0

=) 2-3m=0

=) 3m=2

=) m= 2/3

Therefore, the value of m is 2/3.

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