Math, asked by jyotinareshsoni, 7 months ago

If (3,-2) is one of the solutions of k× -3y =21 then k =..............​

Answers

Answered by vaishakh2005
0

Answer:

put value of x and y on the equation

therefore kx-3y=21

becomes 3k-3(-2)=21

3k+6=21

3k=21-6

3k=15

k=15/3

k=5

hence value of k is 5

Answered by sriharithamudapaka15
0

Answer :

K = 5

Explanation:

Given that (3 , -2) is one of the solution of Kx - 3y = 21 --------(1)

So, we consider (3, -2) will be x and y.

now, These x and y values are substitute in equation (1) then we obtained k value.

kx - 3y = 21

k (3) -3 (-2) = 21

3k +6 = 21

3k = 21-6

3k = 15

k = 15/3

k = 5

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