Question

If (3,2) lies on line x-y=a, then perpendicular distance of point (-4a,3) from y-axis is *​

Answer 1

Answer:

Perpendicular distance of point (- 4a, 3) from Y - axis = - 4.

Explanation:

As the line of equation x - y = a passes through (3, 2), then it must be a solution to it.

Therefore, x - y = 3 - 2 = 1 = a

Hence, (- 4a, 3) = (- 4, 3).

Now, perpendicular distance = abscissa of point (- 4, 3) = - 4.