Question

if 3^2x+1 divide 9=27 , find x

Answer 1

heya dear

here your goes like this dear !!

3^(2x+1) / 9 = 27

by transposing 9 from LHS to RHS then it will be ( ×9 )

3^(2x+1) = 27×9

3^(2x+1) = 243

3^(2x+1) = 3^5

bases are equal , so equate powers

2x+1 = 5

by transposing 1 frm LHS to RHS then it will be (-1)

so now , 2x = 5-1

2x = 4

x = 4/2

x = 2


i hope it helped you :)

Answer 2

The values of $x$ is $2$.

Given-The equation is $\frac{3^{2x+1}}{9}=27$

Find the value of $x$

Given equation is

$\frac{3^{2x+1}}{9}=27$

$3^{2x+1}=27\times 9$

$3^{2x+1}=243$

$3^{2x+1}=3^5$

On comparing base is same

So,

$2x+1=5\\2x=4\\x=2$

Hence, the value of $x$ is $2$.

#SPJ2