If (3^3)^2=9^x then 5^x=_
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Answer:
x=3+3⅓+3⅔
or,(x−3)=3⅓+3⅔
Therefore,
(x−3)3=(3⅓+3⅔)3
or,x3−27−9x2+27x=3+9+3×3(3⅓+3⅔)
or,x3−27−9x2+27x=12+9(x−3)[Puttingthevalue(x−3)=(3⅓+3⅔)]
or,x3−27−9x2+27x=12+9x−27
or,x3−27−9x2+27x−12−9x+27=0
or,x3−9x2+18x−12=0
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