Question

if(3,4) lies on kx-6y=12, find the value of k​

Answer 1

If (3, 4) lies on the following equation, then

x= 3

y= 4

Replacing values,

$3k - 6(4) = 12$

$3k - 24 = 12$

$3k = 12 + 24$

$3k = 36$

$k = \frac{36}{3}$

$k = 12$

Answer 2

Answer:

kx-6y=12

put x=3,y=4 in above equation

then k×3-6×4=12

3k-24=12

3k=12+24

3k=36

k=36÷3

k=12