Question

If (√3+4)power 2=a+b√3 then find a and b​

Answer 1

Answer:

a= 19

b = 8

is the solution to the question

Answer 2

Answer:given (root 3+4)²=a+b root3

(root3+4)²=3+8root3+16

3+8root3+16=a+b root 3-----------A

19+8root3=a+broot3

19+8root3÷root 3=a+b---------------(1)

19+8root3 ÷root 3 - a=b

FromA

3+8root3+16=a+19+8root3 ÷root 3 ×root3

3+8root3 +16 =a+19+8root3

3+16=a+19

19-19=a

a=0

From (1)

a+b=19+8root3 ÷root 3

But a=0 ie

0+b=19+8root3 ÷root 3

b=19+8root3 ÷root 3

So we can show that

a=0;b=19 +8root3 ÷root 3

Step-by-step explanation: