if 3.42 gram of sucrose is dissolved in 18 gram of water in a breaker estimate the number of oxygen atoms in the breaker
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Explanation:
Molar mass of sucrose = 342 g
No. of oxygen atoms in 342 g of (C 12 H22 O11) =11×NA
∴ No. of oxygen atoms in 3.42 g of (C 12 H22 O11 ) = 11×NA ×3.42 /342 = 0.11NA
No. of oxygen atoms in 18g of H2O =1NA
∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11NA + 1NA =1.11NA. =1.11×6.02×10²³ =6.68×10²³ .
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