Question

if 3^4x=(81) and 10^1/y=0.001,Find the value of 2^-x+4y

Answer 1

Hello Mate!

3^( 4x ) = 81 and 10^( 1/y ) = 0.001

3^( 4x ) = 3^4 and 10^( 1/y ) = 1/1000

3^( 4x ) = 3^4 and 10^( 1/y ) = 10^( - 3 )

Now,as per bases are common,

4x = 4 and 1/y = - 3
x = 4/4 and 1 = - 3y
x = 1 and y = - 1/3

So 2 ^ ( - x + 4y ) = 2 ^ ( - 1 + 4 ( - 1/3 ))
2 ^ ( - 1 - 4/3 ) = 2 ^ ( -7/3 )

Or, if you mean by 2^( - x ) + 4y
2^( - 1 ) + 4 ( - 1/3) = 1 /2 - 4/3
= ( 3 - 8 )/6 = - 5/6

Hope it helps☺!✌