Question

If 3^4x = 9^x-2 , find 2^1+x

show the method​

Answer 1

Answer:

$3 {}^{4x} = 9 {}^{x - 2}$

$3 {}^{4x} = 3 {}^{2(x - 2)}$

$4x = 2(x - 2)$

4x = 2x - 4

4x - 2x = -4

2x = -4

x = -2

$2 {}^{1 + x}$

$2 {}^{1 + ( - 2)}$

$2 {}^{1 - 2} = 2 {}^{ - 1} = \frac{1}{2}$

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Answer 2

Answer:

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