Question

if 3× +4y = 18 and xy =6, find the value of 9×2 + 16y 2/ 3x - 4y =18​

Answer 1

Answer:

3x+4y=18

Squaring on both sides

(3x+4y)^2=324

(3x)^2+(4y)^2 +24xy=324

We have,

xy =6

9x^2+16y^2+144=324

So

9x^2+16y^2= 180