Math, asked by varshu02, 7 months ago

if (3/5)^1-2x = (5/3)^3 , Then x equals to?​

Answers

Answered by itzcrazyboy47
6

Answer:

(3/5)^1–2x = (5/3)^3 Possible intermediate steps Solve for x: (3/5)^1–2x=(5/3)^3 Put each ... What is the value of x? ... I squared the (-x) ^ 2 first and got x then multipled it by 2, so I got - 2x.

Step-by-step explanation:

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Answered by chakladershreyasi
7

Answer:

(3/5)^1–2x = (5/3)^3

ᴘᴏssɪʙʟᴇ ɪɴᴛᴇʀᴍᴇᴅɪᴀᴛᴇ sᴛᴇᴘs

sᴏʟᴠᴇ ғᴏʀ x:

(3/5)^1–2x=(5/3)^3

ᴘᴜᴛ ᴇᴀᴄʜ ᴛᴇʀᴍ ɪɴ 3/5–2x ᴏᴠᴇʀ ᴛʜᴇ ᴄᴏᴍᴍᴏɴ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ 5: 3/5–2x=3/5–10x/5:

(3/5–10x/5)=(5/3)^3

3/5–10x/5=3–10x/5

3–10x/5=(5/3)^3

(5/3)^3=5^3/3^3

3–10x\5=5^3/3^3

5^3=5*5^2

3–10x/5=5*5^2/3^3

3^3=3*3^2

3–10x/5=5*5^2/3*3^2

3^2=9

3–10x/5=5x5^2/3*9

5^2=25

3–10x/5=5*25/3*9

3*9=27

3–10x/5=5*25/27

5*25=125

3–10x\5=125/27

ᴍᴜʟᴛɪᴘʟʏ ʙᴏᴛʜ sɪᴅᴇs ᴏғ 3–10x/5=125/27 ʙʏ 5:

5(3–10x)/5=5*125/27

5*125=625

3–10x=625/27

sᴜʙᴛʀᴀᴄᴛ 3 ғʀᴏᴍ ʙᴏᴛʜ sɪᴅᴇs

(3–3)-10x=625/27–3

3–3=0

-10x=625/27–3

ᴘᴜᴛ 625/27–3 ᴏᴠᴇʀ ᴛʜᴇ ᴄᴏᴍᴍᴏɴ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ 27. 625/27 -3=625/27+27(-3)/27:

-10x=625/27–3*27/27

27(-3)=-81

-10x=625/27+-81/27 +-=-

625/27 - 81/27 = 625–81/27

-10x=625–81/27

625–81=544

-10x=544/27

ᴅɪᴠɪᴅᴇ ʙᴏᴛʜ sɪᴅᴇs ᴏғ -10x=544/27 ʙʏ -10

-10x/-10=1/-10*1/27*544

-10/-10=1

x=-1/-10*1/27*1/544

ᴛʜᴇ ɢʀᴇᴀᴛᴇsᴛ ᴄᴏᴍᴍᴏɴ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ ᴏғ 544 ᴀɴᴅ -10 ɪs 2, sᴏ 544/27*(-10)=2*272\27(2(-5))=2/2*272/27*(-5)=272/27*(-5)

x=272/27*(-5)

27(-5)=135

x=272/-135

ᴍᴜʟᴛɪᴘʟʏ ɴᴜᴍᴇʀᴀᴛᴏʀ ᴀɴᴅ ᴅᴇɴᴏᴍɪɴᴀᴛᴏʀ ᴏғ 272/-135 ʙʏ -1:

ᴀɴsᴡᴇʀ:

x=-272/135

-272/135=-2.0148

-272/135=-2.0148

sᴏ

ᴀɴsᴡᴇʀ:

x=-2.0148

Step-by-step explanation:

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ʏᴏᴜ ❣️ ғᴏʟʟᴏᴡ ᴍᴇ

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