If 3+5=16;7+9=64;10+12=121 then 11+3=?
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Answered by
2
The rule is: a+b=(a+b2)2
3+5=(3+52)2 etc.
∴11+3−(11+32)2−49
Answered by
0
Answer:
34
Step-by-step explanation:
3 × 5 = 15 ± 1 = 16
7 × 9 = 63 ± 1 = 64
10 × 12 = 120 ± 1 = 121
So,
11 × 3 = 33 + 1 = 34
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