If 3−√5/ 3+2√5 = a √5 - 19/ 11 , find a
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3− (√5/ 3)+ (2√5) = a √5 - (19/ 11)
3− (√5/ 3)+ (2√5) + (19/ 11) = a √5
(3 + (19/11)) + ((√5/ 3)+ (2√5)) = a√5
(33+19)/11 + (√5+6√5)/3 = a√5
52/11 + 7√5/3 = a√5
(156 + 77√5)/33 = a√5
a = (156 + 77√5)/33√5
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