Question

if 3+5+7+9....n=288 what is the value of n?​

Answer 1

Answer:

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Answer 2

Answer:

Series is 3+5+7+9+.....

which is in A.P. where,

First term a=3

and Common difference, d=a

2

−a

1

=5−3=2

Sum of n terms, S

n

=288

S

n

=

2

n

{2a+(n−1)d}

So,

2

n

{2(3)+(n−1)2}=288

n{6+2n−2}=576

2n

2

+4n=576

n

2

+2n−288=0

n

2

+18n−16n−288=0

(n+18)(n−16)=0

n=−18 or n=16

n is no. of terms which cannot be negative.

So, n=16