Question

if 3/5 is 0 the polynomial x2+k(x)+k then find k ​

Answer 1

Answer:

Given:

• $\dfrac{3}{5}$ is the zero of p(x)
• p(x) = x² + k(x) + k

To find:

• Value of k

$\sf{\underline{Solution:-}}$

As $\dfrac{3}{5}$ is the zero of polynomial , we can write it as $p \left(\dfrac{3}{5}\right) = 0$

☘ Writing it as in this form ,

➫$p \left( \dfrac{3}{5} \right) = 0$

➫$\left( \dfrac{3}{5} \right)^2 + k \left( \dfrac{3}{5} \right) + k = 0$

➫$\dfrac{9}{25} + \dfrac{3k}{5} + k = 0$

➫$\dfrac{9}{25} + \dfrac{3k + 5k}{5} = 0$

➫$\dfrac{9}{25} + \dfrac{8k}{5} = 0$

➫$\dfrac{8k}{5} = \dfrac{-9}{25}$

➫$k = \dfrac{-9}{25} \times \dfrac{5}{8}$

➫$k = \dfrac{-9}{40}$

•°•Value of k is $\bf{\dfrac{-9}{40}}$