If 3+√5 is one root then find the quadratic equation
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hi mate,
solution:
take conjugate pair of 3+√5 is 3 - √5
Given ->
3 - √5 and 3 + √5 are zeros of a polynomial
let p(x) be required polynomial
====> x - (3 + √5) and x - (3 - √5) are factors of p(x)
====> [x - (3 + √5)] [x - (3 - √5) is required polynomial
= [x - 3 - √5] [x - 3 + √5]
= x - 3x + √5x - 3x + 9 - 3 √5 - √5x
+ 3 √5 -5
= x² - 6x + 4
i hope it helps you.
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