if 3/5 of a no. exceeds its 2/7 by 44,find the number.
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Then by the given question,
x×3/5=x×2/7+44
or, 3x/5-2x/7=44
or, (21x-10x)/35=44
or, 11x=44×35
or, x=(44×35)/11
or, x=4×35
or, x=140
x×3/5=x×2/7+44
or, 3x/5-2x/7=44
or, (21x-10x)/35=44
or, 11x=44×35
or, x=(44×35)/11
or, x=4×35
or, x=140
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