Question

If 3/5 of a number exceeds it's 2/7 by 44,find the number.

Answer 1

$\huge{\red {\mathfrak {Question:-}}}$

• If $\dfrac {3}{5}$ of a number exceeds it's $\dfrac {2}{7}$ by 44, find the number.

$\huge{\pink {\mathfrak {Solution:-}}}$

Let the required number be x.

Atq,

$\implies x\times \dfrac{3}{5} = x \times \dfrac{2}{7} + 44 \\ \\ \implies \dfrac{3x}{5} = \dfrac{2x}{7} + 44 \\ \\ \implies \dfrac{3x }{5} - \dfrac{2x}{7} = 44 \\ \\ \implies \dfrac{21x - 10x}{35} = 44 \\ \\ \implies \dfrac{11x}{35} = 44 \\ \\ \implies 11x = 35 \times 44 \\ \\ \implies x = \dfrac{35 \times 44}{11} \\ \\ \implies x = 35 \times 4 \\ \\\implies x = 140$

$\green {\therefore{\tt {The\:required\:number\:is\:140.}}}$

$\rule {307}{2}$