Question

if 3/5 p = 7/9 Q = 4/5 R then what is the ratio of P Q and R respectively​

Answer 1

Here, if the question is considered as (3/5) P = (7/2) Q = (7/5) R, then P:Q:R= 35:6:15

But if question is considered as 3/(5P) = 7/(2Q) = 7/(5R) ,then p:Q:R = 6:35:14

I'm solving here the 2nd part..

3/ 5P = 7/ 2Q = 7/ 5R = K

=> 3 = 5KP . . . . . .. . . . . . . .(1)

7 = 2KQ . . . . . . . . . . . . .(2)

7 = 5KR . . . . . . . . . . .(3)

By eq (1) ÷ (3)

3/7 = 5KP/5KR

=> P/R = 3/7 . . . . . . . . . . . .(4)

Now, eq (2) ÷ eq(3)

2Q/5R = 1/1

=> 5R = 2Q

=> R/Q = 2/5 . . . . . . . . . . .(5)

=> when R is 2x , Q is 5x

Therefore, when R is 7x, Q = 35x/2x = 35/2

This way, now P: Q: R =

3 : 35/2 : 7

= (6 : 35 : 14)

Answer 2

Answer:

Step-by-step explanation: