Question

if [(3+√7)/(3-√7)+(3-√7)/3+√7)]=a+b√2,find the value of a and b​

Answer 1

Answer:

a = 16 and b = 0.

Step-by-step explanation:

  $\frac{3+\sqrt{7} }{3-\sqrt{7} } +\frac{3-\sqrt{7}}{3+\sqrt{7}}$

= $\frac{9+7+6\sqrt{7}+9+7-6\sqrt{7}}{9-7}$

= $\frac{32}{2}$

= $16.$

Here,  $a+b\sqrt{2} =16 =16+0\sqrt{2}$

Therefore, a = 16 and b = 0.