Question

If 3+√7/3-√7=a+b√7, then find the value of “a” and “b”.


Pls ASAP​

Answer 1

Answer:

May be,a=3 andb=-2|3 by equates both sides

Answer 2

Answer:

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } = a + b \sqrt{7} \\ \\ \frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 - \sqrt{7} } = a + b \sqrt{7} \\ \\ \frac{(3 + \sqrt{7}) {}^{2} }{(3) {}^{2} - ( \sqrt{7}) {}^{2} } = a + b \sqrt{7} \\ \\ \frac{9 + 7 + 3 \sqrt{7} }{9 - 7} = a + b \sqrt{7} \\ \\ \frac{16 + 3 \sqrt{7} }{2} = a + b \sqrt{7} \\ \\ \frac{16}{2} + \frac{3}{2} \sqrt{7 } = a + b \sqrt{7} \\ \\ 8 + \frac{3}{2} \sqrt{7} = a + b \sqrt{7 } \\ \\ hence \: a = 8 \: and \: b = \frac{3}{2}$