If = 3 + √8 , ℎ +1
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lim[h(8+h)1/31−2h1]
00 form, so applying L- hospital rule,
h→0lim[2(8+h)1/3+32h(8+h)−2/3][3(8+h)2/3−1]
⇒h→0lim[2(8)1/3+0−1/3(8)2/3]=[6(8)−1]=481
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