If 3,8,13,18 are in a sequency then find that which term is 128.
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1
answer will be 26 th term
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0
these are in ap a+n-1*d
128=3+n-1*5
128-5\5=n-1
25+1=n
n=26
128=3+n-1*5
128-5\5=n-1
25+1=n
n=26
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